[License-discuss] Question about Python 2.0 license

Gregor Hoffleit gregor at hoffleit.de
Fri Feb 12 11:52:46 UTC 2021


>From what I can see, the license text on the OSI site ( [ https://opensource.org/licenses/Python-2.0 | https://opensource.org/licenses/Python-2.0 ] ) is in fact copied from the license of Python 2.7.5: [ https://www.python.org/download/releases/2.7.5/license/ | (https://www.python.org/download/releases/2.7.5/license/ ] ). 

The history of the Python license had a few rough edges. The Python project website has a short history of Python and its license: https://docs.python.org/3/license.html 

Most important, there was a short period in 2000/2001 in which Python was distributed with licenses which were not compatible with the GPL. Namely the licenses of Python 1.6, 2.0 and 2.1. This problem was later on fixed with changes to the licenses in 1.6.1, 2.0.1 and 2.1.1. 

So the license of Python 2.0 was substantially different from 2.0.1 and different from the licenses of later Python versions. 

I would have to browse through my mail archives regarding the details of the problems. 

Best regards, 
Gregor Hoffleit 

> Von: "Candice Wright" <timelessdevotion at gmail.com>
> An: license-discuss at lists.opensource.org
> Gesendet: Donnerstag, 11. Februar 2021 18:38:04
> Betreff: [License-discuss] Question about Python 2.0 license

> Hi everyone!

> I’m trying to find out why the Python 2.0 license listed on OSI and SPDX differs
> some from the Python license listed on their site. I help with ClearlyDefined,
> which uses SPDX identifiers to identify project licenses, but the difference in
> the license text is having some of us think we shouldn't use 'Python-2.0' for
> Python projects since it isn’t a match.

> I’m not very familiar with the history of Python and the license, but I couldn’t
> find the version listed on OSI being used in the Python projects I have come
> across.

> Can someone help me understand why there is a difference and if we can update
> the wording to match the current Python license text?

> Thank you,

> Candice

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