Is inherited class a derivative work?
Rod Dixon, J.D., LL.M.
rdixon84 at home.com
Mon Oct 22 01:20:29 UTC 2001
The answer is no. You might recall that trademark law does not grant the TM owner the right to control all use of the mark. If the use is outside the scope of TM usage (namely, the identification of source), it is unlikely that the use invokes in TM rights at all...particularly under the facts raised in the question, here.
Rod
-----Original Message-----
From: "Angelo Schneider" <angelo.schneider at oomentor.de>
Sent: 10/19/01 9:33:08 AM
Cc: "license-discuss at opensource.org" <license-discuss at opensource.org>
Subject: Re: Is inherited class a derivative work?
Hi all!
Rob Myers wrote:
[...]
>
> Out of curiosity could function/method names be trademarked to regulate
> their calling? :-)
In europe not.
APIs and even data base schemata (what you get after executing a
sequence of SQL create table statements) are explicitly noted as: not
copyright able, not patent able, not trademark able.
So a program written relying on an API never touches even any IP right
associated
with the original work yielding that API (well linking or includign the
original work (in-)to the distribution brings us back to the topic).
>
> - Rob.
>
Angelo
----------------------------------------------------------------------
Angelo Schneider OOAD/UML Angelo.Schneider at oomentor.de
Putlitzstr. 24 Patterns/FrameWorks Fon: +49 721 9812465
76137 Karlsruhe C++/JAVA Fax: +49 721 9812467
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